SOLUTION: Find three consecutive even numbers such that the second and third numbers exceeds the first number by 14.

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Question 903468: Find three consecutive even numbers such that the second and third numbers exceeds the first number by 14.
Answer by Stitch(470) About Me  (Show Source):
You can put this solution on YOUR website!
If the first number is X, then the next even number would be X+2.
The next even number after X+2 would be X+4.
So: X+%2B+14+=+%28X%2B2%29+%2B+%28X%2B4%29
Simplify
X+%2B+14+=+X+%2B+2+%2B+X+%2B+4
Combine like terms
X+%2B+14+=+2X+%2B+6
Subtract X from both sides.
14+=+X+%2B+6
Subtract 6 from both sides.
highlight%288+=+X%29
-------------------------
X+2 ---> (8) + 2 = 10
X+4 ---> (8) + 4 = 12
The three consecutive even numbers are 8, 10 & 12