SOLUTION: A man built a walk of uniform width around a rectangular pool. If the area of the walk is 145 square feet and the dimensions of the pool are 9 feet by 15 feet, how wide is the walk
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Question 903429: A man built a walk of uniform width around a rectangular pool. If the area of the walk is 145 square feet and the dimensions of the pool are 9 feet by 15 feet, how wide is the walk? Answer by ewatrrr(24785) (Show Source):
Hi, .
Total Area of pool and walk = (9*15 + 145)ft^2
(9+x)(15+x) = 280ft^2
135 + 24x + x^2 = 280
x^2 + 24x - 145 = 0 (Tossing out the negative solution for unit measure)
(x-5)(x+29) = 0
x = 5ft
walk (on each side)= 2.5ft wide
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