SOLUTION: I have three questions: 1. y-2 > |x+4| 2. y< |x| + x 3. y< -2|x-3|

Algebra ->  Rational-functions -> SOLUTION: I have three questions: 1. y-2 > |x+4| 2. y< |x| + x 3. y< -2|x-3|       Log On


   

Question 902824: I have three questions: 1. y-2 > |x+4|
2. y< |x| + x
3. y< -2|x-3|
Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
First and last are similar. The middle one is different. The critical value for x is 0, where the sign of the value for x changes.

x%3E=0 means y%3Cx%2Bx, y%3C2x.
This starts at greater than (0,0) and moves with slope of 2 to the right. y is all values less than y=2x.

x%3C0 means y%3C-x%2Bx, y%3C0 for all x.



graph%28300%2C300%2C-4%2C4%2C-4%2C4%2Cy%3Cabs%28x%29%2Bx%29