Question 902820: cos θ = − 10/13
,
tan θ < 0
what is the sin, tan, csc, cot?
Any help would be greatly appreciated
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! cos θ = − 10/13,
tan θ < 0
what is the sin, tan, csc, cot?
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reference angle θ is in quadrant II in which cos<0, sin>0, tan<0
sinθ=√(1-cos^2θ)=√(1-100/169)=√(69/169)=√69/13
tanθ=sinθ/cosθ=-√69/10
cscθ=1/sinθ=13/√69
cotθ=1/tanθ=-10/√69
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