SOLUTION: how many liters of a 10% acid solution must be mixed with a 50% acid solution in order to obtain 15 liters of a 30% solution?

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Question 902758: how many liters of a 10% acid solution must be mixed with a 50% acid solution in order to obtain 15 liters of a 30% solution?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
.50x + .10(15L-x) = .30(15L)
x = .20(15L)/.40 = 7.5L, amount of 50%. Amount at 10% = 15-x