SOLUTION: Find the value of {{{a^2+2ab+b^2}}} when a=2, b=1.

Algebra ->  Square-cubic-other-roots -> SOLUTION: Find the value of {{{a^2+2ab+b^2}}} when a=2, b=1.      Log On


   

Question 902613: Find the value of a%5E2%2B2ab%2Bb%5E2 when a=2, b=1.
Answer by Jc0110(165) About Me  (Show Source):
You can put this solution on YOUR website!
Substitute a=2, b=1 into a%5E2%2B2ab%2Bb%5E2.
a%5E2%2B2ab%2Bb%5E2 = 2%5E2%2B2%282%29%281%29%2B1%5E2 = 4%2B4%2B1 = 9