SOLUTION: Find three consecutive odd integers so that 4 times the sum of the first two is 31 more than 7 times the third integer.

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Question 902368: Find three consecutive odd integers so that 4 times the sum of the first two is 31 more than 7 times the third integer.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive odd integers: (x-2), x, (x+2)

4((x-2) + x) > 7(x+2)
4(2x-2) > 7(x+2)
8x-8 > 7x+14
x > 22

The smallest possible value of the smallest integer is 21.