Question 902315: How many liters of a 85% acid solution must be added to 12 liters of a 25% acid solution to produce a 49% acid solution? Found 3 solutions by stanbon, lwsshak3, richwmiller:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How many liters of a 85% acid solution must be added to 12 liters of a 25% acid solution to produce a 49% acid solution?
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Equation:
acid + acid = acid
0.85x + 0.25*12 = 0.49(x + 12
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85x + 25*12 = 49x + 49*12
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36x = 24*12
x = (2/3)12
x = 8 liters (amt. of 85% solution needed)
12-x = 4 liters (amt. of 25% solution needed)
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Cheers,
Stan H.
You can put this solution on YOUR website! How many liters of a 85% acid solution must be added to 12 liters of a 25% acid solution to produce a 49% acid solution?
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let x=amt of 85% solution to add
85%x+25%*12=49%(12+x)
.85x+3=5.88+.49x
.36x=2.88
x=8
amt of 85% solution to add=8 liters
You can put this solution on YOUR website! 0.85*x+0.25*12=0.49(12+x)
0.85*x+3=5.88+0.49x
0.85x-0.49x=5.88-3
0.36x=2.88
x=8 liters at 85% is added to 12 liters of 25% to get 20 liters at 49%
check
0.85*8+0.25*12=0.49(12+8)
6.8+3=0.49(20)
9.8=9.8
ok
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