SOLUTION: Adrienne wants to catch a train that leaves at 10:40 AM and must ride her bike to the station, which is 6 miles away. The first 2 miles are uphill, the next 2 miles are flat, and

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Adrienne wants to catch a train that leaves at 10:40 AM and must ride her bike to the station, which is 6 miles away. The first 2 miles are uphill, the next 2 miles are flat, and       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 902278: Adrienne wants to catch a train that leaves at 10:40 AM and must ride her bike to the station, which is 6 miles away. The first 2 miles are uphill, the next 2 miles are flat, and the last 2 miles are downhill. She can ride at 2 MPH going uphill, 3 MPH on level ground, and 4 MPH going downhill. It will take her 5 minutes to lock up her bike and get to the train once she gets to the station. If she leaves her house at 8:35, will she catch the train? Explain. (Show your work)
^ Word for word on my daughter's homework. Please help. Thanks in advance. :)
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Rate*Time=Distance
Time=Distance/Rate
t=D%2FR
t%5B1%5D=2%2F2=1hr
t%5B2%5D=2%2F3=2%2F3hr
t%5B3%5D=2%2F4=1%2F2hr
So her total time riding is,
T=1%2B2%2F3%2B1%2F2
T=6%2F6%2B4%2F6%2B3%2F6
T=13%2F6 hr
or
T=2%261%2F6hr
or
T=2 hours, 10 minutes.
Add the 5 minutes to lock up her bike.
T=2:15
Add to 8:35.
8:35+2:15=10:50.
No, she missed the train by 10 minutes.