SOLUTION: how many gallons of 30% antifreeze should be mixed with 10 gallons of 75% anitfreeze to obtain a 55% antifreeze mixture

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Question 902272: how many gallons of 30% antifreeze should be mixed with 10 gallons of 75% anitfreeze to obtain a 55% antifreeze mixture
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
0.3*x+0.75*10=0.55(10+x)
0.3*x+7.5=5.5+0.55x
0.3x-0.55x=5.5-7.5
-0.25x=-2
x=8 liters at 30% is added to 10 liters of 75% to get 18 liters at 55%
check
0.3*8+0.75*10=0.55(10+8)
2.4+7.5=0.55(18)
9.9=9.9
ok