SOLUTION: The length of a rectangle is 4 inches greater than twice the width. If the diagonal is 2 inches more than the length, find the dimensions of the rectangle.
Algebra ->
Customizable Word Problem Solvers
-> Misc
-> SOLUTION: The length of a rectangle is 4 inches greater than twice the width. If the diagonal is 2 inches more than the length, find the dimensions of the rectangle.
Log On
Question 902256: The length of a rectangle is 4 inches greater than twice the width. If the diagonal is 2 inches more than the length, find the dimensions of the rectangle. Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! Pythagorean Theorem
(2w+4)^2 + w^2 = (2w+6)^2
w^2 -8x -20 = 0
(w - 10)(w+2) = 0, w = 10 and L = 24
and
100 + 576 = 676