SOLUTION: Find the number whose third, fourth and fifth parts added together equals 47. With a solution please. Thank you.

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Question 902150: Find the number whose third, fourth and fifth parts added together equals 47.
With a solution please. Thank you.
Found 2 solutions by Edwin McCravy, MathLover1:
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
expr%281%2F3%29x%2Bexpr%281%2F4%29x%2Bexpr%281%2F5%29x=47

Multiply through by the LCD = 60

60%2Aexpr%281%2F3%29%2Ax%2B60%2Aexpr%281%2F4%29%2Ax%2B60%2Aexpr%281%2F5%29%2Ax=60%2A47

20x%2B15x%2B12x=60%2A47

47x=60%2A47

x=60

Checking:

1%2F3 of 60 is 20
1%2F4 of 60 is 15
1%2F5 of 60 is 12
--------------
    total = 47  

Edwin

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

let's number be x
third of the number is x%2F3
fourth of the number is x%2F4
and fifth of the number is x%2F5
given: third, fourth and fifth parts added together equals 47
so, x%2F3%2Bx%2F4%2Bx%2F5=47 ...solve for x

x%2F3%2Bx%2F4%2Bx%2F5=47...find common denominator; for 3,4 and 5 will be 60
20x%2F%2820%2A3%29%2B15x%2F%2815%2A4%29%2B12x%2F%2812%2A5%29=47
20x%2F60%2B15x%2F60+%2B12x%2F60+=47
%2820x%2B15x+%2B12x%29%2F60+=47
47x%2F60+=47
47x+=47%2A60
x+=47%2A60%2F47
x+=60
check:

third of the number is x%2F3=60%2F3=20
fourth of the number is x%2F4=60%2F4=15
and fifth of the number is x%2F5=60%2F5=12
the sum: 20%2B15%2B12=47