SOLUTION: 5lgx^3 -3lgx^2 = 12 thx i couldnt figure out to send a tutor a private msg or comment on a sulotion the game me , any help?

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Question 902106: 5lgx^3 -3lgx^2 = 12


thx
i couldnt figure out to send a tutor a private msg or comment on a sulotion the game me , any help?
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Better notation in pure text: 5*log((x^3))-3*log((x^2))=12
With rendering tags, 5%2Alog%28%28x%5E3%29%29-3%2Alog%28%28x%5E2%29%29=12

Using logarithm rules and algebra,
5%2A3%2Alog%28%28x%29%29-2%2A3%2Alog%28%28x%29%29=12
Divide by 3.
5%2Alog%28%28x%29%29-2%2Alog%28%28x%29%29=4
log%28%28x%5E5%29%29-log%28%28x%5E2%29%29=4
log%28%28x%5E5%2Fx%5E2%29%29=4
log%28%28x%5E3%29%29=4

But next, knowing which base is necessary. Your exponential form for base b would be
b%5E4=x%5E3

Is b=10 for common logs?
10000=x%5E3
The easy way is cube root of 10000, root%283%2C10000%29.
Would be 10%2Aroot%283%2C10%29.