SOLUTION: find two consecutive odd integers such that their product is 107 more than 6 times their sum

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Question 901995: find two consecutive odd integers such that their product is 107 more than 6 times their sum
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive odd integers: x, (x+2)

x(x+2) = 107 + 6(x + (x+2))
x^2 + 2x = 6(2x+2) + 107
x^2 + 2x = 12x + 119
x^2 - 10x - 119 = 0
(x - 17)(x + 7) = 0

The integers are -7 and -5 or 17 and 19.