SOLUTION: The length of a rectangle is 5 m more than twice the width, and the area of the rectangle is 42 m^2 . Find the dimensions

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Hi,

     .

a = Lw = (2w+5)w

2w^2 + 5w = 42m^2

2w^2 + 5w -42 = 0

(2w -7)(x+6) = 0, using Positive Solution only

 w = 7/2 m

L = 12m