SOLUTION: 1. Prove that (1-cosA) (1-secA) = tan A sinA 2. Prove that secA (1-sinA) (secA+tanA) = 1

Algebra ->  Trigonometry-basics -> SOLUTION: 1. Prove that (1-cosA) (1-secA) = tan A sinA 2. Prove that secA (1-sinA) (secA+tanA) = 1      Log On


   

Question 901608: 1. Prove that (1-cosA) (1-secA) = tan A sinA
2. Prove that secA (1-sinA) (secA+tanA) = 1
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Prove that (1-cosA) (1-secA) = tan A sinA
I think it should be (1+sec A)
(1-cos A )(1+sec A)
1+secA-cos A -cos A. sec A
1+sec A - cos A-1
1/cos A -cos A
(1-cos^2 A)/ cos A
sin^2 A/cos A
sin A/cos A * sin A
tan A * sin A

2. Prove that secA (1-sinA) (secA+tanA) = 1
sec A-sec A*sin A (sec A+tan A)
(sec a-tan A)(sec A+ tan A)
sec^2A - tan^2A
=1