SOLUTION: solve (x-5)^2=7 A)-5+(minus underneath the plus) square root of 7 B) 5+(minus underneath the plus) square root of 7 C) +(minus underneath the plus) square root of 54 D) +(

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: solve (x-5)^2=7 A)-5+(minus underneath the plus) square root of 7 B) 5+(minus underneath the plus) square root of 7 C) +(minus underneath the plus) square root of 54 D) +(      Log On


   

Question 90159: solve
(x-5)^2=7
A)-5+(minus underneath the plus) square root of 7
B) 5+(minus underneath the plus) square root of 7
C) +(minus underneath the plus) square root of 54
D) +(minus underneath the plus)54
Answer by tutorcecilia(2152) About Me  (Show Source):
You can put this solution on YOUR website!
%28%28x-5%29%5E2%29 = 7 [take the square root of both sides of the equation]
%28sqrt%28x-5%29%5E2%29 = %28sqrt%287%29%29
.
x-5 = %28%2B-sqrt%287%29%29 [add (5) to both sides of the equation]
x = 5%2B-sqrt%287%29%29%29
Answer: B