SOLUTION: I have a logarithmic expression to condense Equation: 3 log (x+1) + 5 log(9x+1)- log(x+1) I know it can be written as log (x+1)^3 + log (9x+1)^5 - log (x+1) but i'm lost

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I have a logarithmic expression to condense Equation: 3 log (x+1) + 5 log(9x+1)- log(x+1) I know it can be written as log (x+1)^3 + log (9x+1)^5 - log (x+1) but i'm lost       Log On


   

Question 901583: I have a logarithmic expression to condense
Equation: 3 log (x+1) + 5 log(9x+1)- log(x+1)
I know it can be written as
log (x+1)^3 + log (9x+1)^5 - log (x+1)
but i'm lost after this how can i condense this further. help
Found 2 solutions by solver91311, stanbon:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


The sum of the logs is the log of the product. The difference of the logs is the log of the quotient.

So






John

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Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
I have a logarithmic expression to condense
Equation: 3 log (x+1) + 5 log(9x+1)- log(x+1)
I know it can be written as
log (x+1)^3 + log (9x+1)^5 - log (x+1)
---------
log[(x+1)^3*(9x+1)^5/(x+1)]
---------
= log[(x+1)^2*(9x+1)^5]
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Cheers,
Stan H.
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