SOLUTION: Thomas is putting a fence around his field. His field is 360 yd long and 225 yd wide. He wants to out a fence post every 3 yd. How many fence posts will Thomas need?

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Thomas is putting a fence around his field. His field is 360 yd long and 225 yd wide. He wants to out a fence post every 3 yd. How many fence posts will Thomas need?      Log On

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Question 901308: Thomas is putting a fence around his field. His field is 360 yd long and 225 yd wide. He wants to out a fence post every 3 yd. How many fence posts will Thomas need?
Answer by harpazo(655) About Me  (Show Source):
You can put this solution on YOUR website!
Let's see.
360/3 = 120
225/3 = 75

P = 2 times width plus 2 times length.
P = 2(75) + 2(120)

P = 150 + 240

P = 390

He will need 390 fences.