Question 901291: A projectile is launched straight up from ground level with an initial velocity of 256 ft/sec. As its falling, its height is given by the formula
h=-16t˛+256t, where h represents height and t represents time.
a) When will the projectile’s height above the ground be 768 ft?
b) When will the projectile hit the ground?
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! A projectile is launched straight up from ground level with an initial velocity of 256 ft/sec. As its falling, its height is given by the formula
h=-16t˛+256t, where h represents height and t represents time.
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h(t) = -16t^2 + 256t for the entire time of flight, not just when falling.
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a) When will the projectile’s height above the ground be 768 ft?
h(t) = -16t^2 + 256t = 768
Solve for t. It's just a quadratic.
If there are 2 solutions, 1 is ascending, 1 is descending.
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b) When will the projectile hit the ground?
When h(t) = 0
Solve for t
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