SOLUTION: Suppose that you need to fence a rectangular play area in your backyard for your child or pet. Further, suppose that you know the length must be 8 feet longer than the width. The b

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Question 901284: Suppose that you need to fence a rectangular play area in your backyard for your child or pet. Further, suppose that you know the length must be 8 feet longer than the width. The back of your house will serve as one side of the fenced area. Note: The perimeter (distance around) of a general rectangle is P = 2L + 2W, and its area is A = L x W. In this situation, P = L + 2W.The area is 8265. What is the area and the preimeter in terms of the lenght?
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
L=w+8, and for enclosing the play area, p=2w+L, and you know a constant area A to be A=wL.


w=L-8 from given information.
p=2w%2BL.
p=2%28L-8%29%2BL
p=2L-16%2BL
highlight%28p=3L-16%29

A=wL
A=%28L-8%29L
highlight%28A=L%5E2-8L%29

When you know or given a value for area A, you can find L and use L to find p.