Question 901199: Factor 4y^4+72y^3+180y^2
Answer by harpazo(655)   (Show Source):
You can put this solution on YOUR website! Factor 4y^4+72y^3+180y^2.
Remove 4y^2 and then divide each term by 4y^2.
4y^4 divided by 4y^2 = y^2
72y^3 divided by 4y^2 = 18y
180y^2 divided by 45
4y^2(y^2 + 18y + 45)
Can we factor what lies in the parenthese a little more?
Yes, we can.
y^2 + 18y + 45 = (y + 3)(y + 15)
The final answer is 4y^2(y + 3)(y + 15)
Did you follow?
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