SOLUTION: I have two equations for this problem, I am just not sure how to solve it. The problem is; At a benefit concert, 900 tickets were sold and $2700 was raised. If there were $2 and $5
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Question 900882: I have two equations for this problem, I am just not sure how to solve it. The problem is; At a benefit concert, 900 tickets were sold and $2700 was raised. If there were $2 and $5 ticket, how many of each were sold?
I have x+y= 900 and then $2x+$5y=$2700 Found 2 solutions by richwmiller, Alan3354:Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! x+y=900,
2*x+5*y=2700
x=900-y
2*(900-y)+5*y=2700
1800-2y+5*y=2700
3*y=900
y=300
x=900-y
x=600 at 2 and y=300 at 5
check
600+300=900
2*x+5*y=2700
2*600+5*300=2700
1200+1500=2700
2700=2700
ok
You can put this solution on YOUR website! I have two equations for this problem, I am just not sure how to solve it. The problem is; At a benefit concert, 900 tickets were sold and $2700 was raised. If there were $2 and $5 ticket, how many of each were sold?
I have x+y= 900 and then $2x+$5y=$2700
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Getting from the "word problem" to 2 eqns is what most can't seem to do. Good work on that.
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x+y= 900
2x+5y=2700 (the $ are not needed)
Multiply the 1st eqn by 2
2x + 2y = 1800
2x + 5y = 2700
-------------------------- Subtract
-3y = -900
y = 300
==========
x+y = 900
x = 600
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