SOLUTION: A student drove a distance of 120 miles at an average speed of 55 mph. How much faster would she have to drive on the return trip to save 30 minutes of driving time?

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Question 900858: A student drove a distance of 120 miles at an average speed of 55 mph. How much faster would she have to drive on the return trip to save 30 minutes of driving time?
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
55t=120,
x(t-1/2)=120
t=120/55
t=24/11=48/22
x(48/22-11/22)=120
x*37/22=120
37x=2640
x=71.35