SOLUTION: five times the larger of two consecutive odd integers is equal to one more than eight times the smaller.

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Question 900478: five times the larger of two consecutive odd integers is equal to one more than eight times the smaller.
Answer by JulietG(1812) About Me  (Show Source):
You can put this solution on YOUR website!
5A = 8B+1
A = B+2 (consecutive odd)
Substitute the value of A from the second equation into the first.
5(B+2) = 8B+1
Distribute
5B+10 = 8B+1
Subtract 1 from each side
5B + 9 = 8B
Subtract 5B from each side
9 = 3B
Divide each side by 3
3 = B
If the smaller number is 3, then the larger is 5.

Prove it:
5*5 = 8*3 + 1
25 = 24 + 1
25 = 25