SOLUTION: 1) Suppose there are 4 different courses to be taken in a certificate programme comprising 4 theory classes (T1,T2,T3 and T4) and practical classes (P1,P2,P3) respectively. If the

Algebra ->  Probability-and-statistics -> SOLUTION: 1) Suppose there are 4 different courses to be taken in a certificate programme comprising 4 theory classes (T1,T2,T3 and T4) and practical classes (P1,P2,P3) respectively. If the       Log On


   



Question 900278: 1) Suppose there are 4 different courses to be taken in a certificate programme comprising 4 theory classes (T1,T2,T3 and T4) and practical classes (P1,P2,P3) respectively. If the table below shows the cross classification of the classes by both the theory and practical classes,Calculate the probability that a class hold at random is of:-
A 1) class T1
2) classT2
3) classT3
4) classT4
B class P1 and Class p3
C 1) class P1 with classP3
2) class T3 with class P2
3) class P2 with class T4
Class distribution between theory and practical classes
Classes P1 P2 P3
T1 30 25 60
T2 55 25 35
T3 45 35 20
T4 60 40 40
2) If the probability that a hunter will hit a target is 3/5 and the hunter aims at the target twice, what is the probability that
A He hits the target twice?
B He hits the target once?
C He hits the target at first attempt and misses the target at second attempt?
D He misses the target twice?

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi
Classes P1 P2 P3 T
T1 30 25 60 115
T2 55 25 35 115
T3 45 35 20 100
T4 60 40 40 140
Total 190 125 155 470
A
1) class T1 115/470
2) classT2 115/470
3) classT3 100/470
4) classT4 140/470
B class P1 and Class p3
C
(1) class P1 with class P3 90/470
2) class T3 with class P2 20/470
3) class P2 with class T4 40/470
p(hit) = 3/5
2 tries
P(2 hits) = (3/5)(3/5)
p(1 hit) = 2(3/5)(2/5) (first 0r Second)
p(f not second) = (3/5)(2/5)
P(2misses) = (2/5)(2/5)