Question 90024: Could you please help me with this problem?
1/(x^2-2x-3)+2/(x^2+2x+1) Thank you!!! Answer by uma(370) (Show Source):
You can put this solution on YOUR website! 1/(x^2-2x-3)+2/(x^2+2x+1)
The first denominator = x^2 - 2x - 3
= x^2 - 3x + x - 3
= x(x-3) +1(x-3)
= (x-3)(x+1)
The second denominator = x^2 + 2x + 1
= x^2 + x + x + 1
= x(x+1) + 1(x+1)
= (x+1)(x+1)
Now the given question is 1/(x-3)(x+1) + 2/(x+1)(x+1)
= [(x+1) + (x-3)]/(x-3)(x+1)(x+1)
= (2x - 2)/ (x-3)(x+1)(x+1)
= 2(x-1)/(x-3)(x+1)(x+1)
Good luck!!!
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