SOLUTION: the remainder when 1!+2!+3!+........+100! is divided by 5

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Question 900235: the remainder when 1!+2!+3!+........+100! is divided by 5
Answer by Edwin McCravy(20064) About Me  (Show Source):
You can put this solution on YOUR website!
1!+2!+3!+...+100! = 1!+2!+3!+4!+ integers divisible by 5 = 

1+2+6+24+ integers divisible by 5 = 33 + integers divisible by 5. 

So when 1!+2!+3!+...+100 is divided by 5, the remainder is 
the same as when 33 is divided by 5.

      6
   5)33
     30
      3

Answer: 3

Edwin