SOLUTION: How many mL of a 60% acid solution must be mixed with a 20% acid solution to produce 200 mL of a 50% acid solution?

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Question 900041: How many mL of a 60% acid solution must be mixed with a 20% acid solution to produce 200 mL of a 50% acid solution?
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
a+b=200,
0.6*a+0.2*b=0.5*200
a=200-b
0.6*(200-b)+0.2*b=100
120-0.6b+0.2*b=100
-0.4*b=-20
b=50
a=200-b
a=150 b=50
check
0.6*150+0.2*50=0.5*200
90+10=100
100=100
ok