SOLUTION: 1. A woman is paid $20 for each day she works and forfeits $4 for each day she is idle. At the end of 25 days she nets $450. How many days did she work?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: 1. A woman is paid $20 for each day she works and forfeits $4 for each day she is idle. At the end of 25 days she nets $450. How many days did she work?      Log On


   



Question 899891: 1. A woman is paid $20 for each day she works and forfeits $4 for each day she is idle. At the end of 25 days she nets $450. How many days did she work?
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
w+i=25,
20w-4*i=450
It doesn't come out whole numbers
about 23 working 2 idle
x+y=25,
20*x-4*y=450
x=25-y
20*(25-y)-4*y=450
500-20y-4*y=450
-24*y=-50
y=2.08333333
x=25-y
x=22.9166667 y=2.08333333
check
22.9166667+2.08333333=25
20*x-4*y=450
20*22.9166667-4*2.08333333=450
458.333333-8.33333333=450
450.0=450
ok