SOLUTION: pam earns $468 per year in simpler interest by investing part of her money at 8% and the rest at 6%. if she invests $2000 more of her money at 8% than she invests at 6%, how much m

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: pam earns $468 per year in simpler interest by investing part of her money at 8% and the rest at 6%. if she invests $2000 more of her money at 8% than she invests at 6%, how much m      Log On

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Question 899766: pam earns $468 per year in simpler interest by investing part of her money at 8% and the rest at 6%. if she invests $2000 more of her money at 8% than she invests at 6%, how much money did she invest at 8%?
Found 2 solutions by mananth, richwmiller:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!

money invested at 6%.-----------x
money at 8% -------------- (x+2000)
pam earns $468 per year
8%(x+2000)+6%x = 468
multiply equation by 100
8(x+2000) +6x = 46800
8x+16000+6x=46800
14x=46800-16000
14x=3800
x= 2000
money invested at 8% = 2000+2000=4000

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
x-y=2000
x=2000+y
0.08*x+0.06*y=468
0.08*(2000+y)+0.06*y=468
160+0.08y+0.06*y=468
0.14*y=308
y=2200 at 6%

x=2000+y
x=4200 at 8%
check
0.08*4200+0.06*2200=468
336+132=468
468=468
ok