SOLUTION: At 8:00am, Catherine leaves on a trip at 45 mi/h.
One hour later, Max decides to join her and leaves along the same route, traveling at 54 mi/h. When will Max catch Catherine?
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-> SOLUTION: At 8:00am, Catherine leaves on a trip at 45 mi/h.
One hour later, Max decides to join her and leaves along the same route, traveling at 54 mi/h. When will Max catch Catherine?
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Question 899609: At 8:00am, Catherine leaves on a trip at 45 mi/h.
One hour later, Max decides to join her and leaves along the same route, traveling at 54 mi/h. When will Max catch Catherine?
Here's what I did:
Distance of Catherine(c)=Distance of Max(m)
c=45(t+1)
m=54t
45(t+1)=54t
45t+45=54t
-45t. -45t
45= 9t
T= 5
So the time Max catches up with Catherine should be 1pm?
But I'm worried this might be incorrect Answer by ewatrrr(24785) (Show Source):
