SOLUTION: 3) You have 480 feet of fencing to enclose a rectangular garden. You want the length of the garden to be 30 feet greater than the width. Find the length and width of the garden i

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: 3) You have 480 feet of fencing to enclose a rectangular garden. You want the length of the garden to be 30 feet greater than the width. Find the length and width of the garden i      Log On


   

Question 899345: 3) You have 480 feet of fencing to enclose a rectangular garden. You want the length of the garden to be 30 feet greater than the width. Find the length and width of the garden if you use all of the fencing.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Length L, width w.
L-w%3E30 and 2w%2B2L=480.

w+L=240
w=240-L
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substitute into the inequality.
L-%28240-L%29%3E30
L-240%2BL%3E30
2L%3E30%2B240
2L%3E270
highlight%28L%3E135%29
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Reuse w+L=240.
L=240-w.
Substitute again, into inequality:
240-w-w%3E30
240-2w%3E30
-2w%3E30-240
2w%3C240-30
2w%3C210
highlight%28w%3C105%29

*--------------------------------------------------------------*
The acceptable interval on L is L%3E135;
and acceptable interval on w is 0%3Cw%3C105.
An equation to relate w and L may be highlight%28w%2BL=240%29, along with the stated restrictions on L and w.
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Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

3) You have 480 feet of fencing to enclose a rectangular garden. You want the length of the garden to be 30 feet greater than the width. Find the length and width of the garden if you use all of the fencing.


Let width of garden be W

Then length = W + 30

2W + 2(W + 30) = perimeter

2(W) + 2(W + 30) = 480

2(W) + 2(W + 30) = 2(240)

W + W + 30 = 240

2W = 240 - 30

2W = 210

W, or width = 210%2F2, or highlight_green%28105%29 feet

Length = 105 + 30, or highlight_green%28135%29 feet