SOLUTION: A sample of 25 patients in a doctor's office showed that they had to wait an average of 35 minutes with a standard deviation of 10 minutes before they could see the doctor. Provid

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Question 899082: A sample of 25 patients in a doctor's office showed that they had to wait an average of 35 minutes with a standard deviation of 10 minutes before they could see the doctor. Provide a 95% confidence interval estimate for the average waiting time of all the patients who visit this doctor. What is the margin of error?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

 Provide a 95% confidence interval 

ME = 1.96[10/sqrt(25)] = 3.92 0r 4

CI:   35 - ME < mu < 35 + ME



CI	z = 1.28155

90%	z =1.645

92%	z = 1.751

95%	z = 1.96  ***

98%	z = 2.326

99%	z = 2.576