SOLUTION: Find two consecutive odd intgers such that the smaller one is sixteen more than one third the larger.

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Question 899069: Find two consecutive odd intgers such that the smaller one is sixteen more than one third the larger.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find two consecutive odd intgers such that the smaller one is sixteen more than one third the larger.
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1st: 2x-1
2nd: 2x+1
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Equation:
2x-1 = (1/3)(2x+1) + 16
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Multiply thru by 3 to get rid of the fraction:
6x -3 = (2x+1) + 48
4x-3 = 49
4x = 52
x = 13
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1st: 2x-1 = 25
2nd: 2x+1 = 27
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Cheers,
Stan H.
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