SOLUTION: Tutor,
I could use some help on this problem. I have been looking at it for a while and I am just not sure how to work through it, any help is appreciated.
Technology. Dr
Algebra ->
Customizable Word Problem Solvers
-> Misc
-> SOLUTION: Tutor,
I could use some help on this problem. I have been looking at it for a while and I am just not sure how to work through it, any help is appreciated.
Technology. Dr
Log On
Question 89898This question is from textbook Beginning Algebra
: Tutor,
I could use some help on this problem. I have been looking at it for a while and I am just not sure how to work through it, any help is appreciated.
Technology. Driving down a mountain, Tom finds that he has descended 1800 ft in elevation by the time he is 3.25 mi horizontally away from the top of the mountain. Find the slope of his descent to the nearest hundredth.
This question is from textbook Beginning Algebra
You can put this solution on YOUR website! Tom finds that he has descended 1800 ft in elevation by the time he is 3.25 mi horizontally away from the top of the mountain. Find the slope of his descent to the nearest hundredth.
-------------
slope = change in vertical height / change of horizontal position
slope = 1800 ft / 3.25 mi
slope = 1800 ft / [(3.35)(5280)] ft
slope = 0.102
=======================
Cheers,
Stan H.
You can put this solution on YOUR website! Draw a picture of a right-triangle.
1800 feet is the height of the triangle, meaning from the top of mountain to where Tom stop.
3.25 mile is the slant of the triangle.
So what you can imagine is that Tom is coming down the slant. When travelled 3.25 miles from the top, he's decended 1800 ft.
********* Step #1: Use to find all sides of the triangle
Where a=1800 ft and c=3.25 miles.
(Note: 1 miles = 5280 feet; so 3.25 miles is 17160 ft.)
becomes
becomes
********* Step #2: Solving slope of decent
slope = Rise/Run.
In this case our Rise=1800; Run=17065
becomes