Question 898703: A man leaves his home every morning at 07h45 for his work which starts at 08h00. The time it takes him to travel to work is normally distributed with mean 10 and SD 2 minutes. According to tables of normal distribution , the proportion of journeys to work that takes him between 10 and 15 minutes is 0.4938. The proportion of journeys to work in the morning for which he will be late for work is ?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A man leaves his home every morning at 07h45 for his work which starts at 08h00. The time it takes him to travel to work is normally distributed with mean 10 and SD 2 minutes. According to tables of normal distribution , the proportion of journeys to work that takes him between 10 and 15 minutes is 0.4938.
The proportion of journeys to work in the morning for which he will be late for work is ?
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z(15) = (15-10)/2 = 2.5
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Note: Late for work means he takes more than 15 minutes to get to work.
P(x > 15 min) = P(z > 2.5) = normalcdf(2.5,100) = 0.0062
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Cheers,
Stan H.
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