SOLUTION: the equation h=16t^2+112t gives the height of an arrow. shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground. fi
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-> SOLUTION: the equation h=16t^2+112t gives the height of an arrow. shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground. fi
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Question 89801: the equation h=16t^2+112t gives the height of an arrow. shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground. find the time it takes for the arrow to reach the height of 180 ft. Answer by tutorcecilia(2152) (Show Source):
You can put this solution on YOUR website! h=-16t^2+112t
180=-16t^2+112t [Let (h) = 180]
0 = -16t^2+112t-180 [set the equation equal to zero]
Use the quadratic formula to factor
x=2.5 seconds at 180 feet
