SOLUTION: given z=2+2i; z=cos(5π/6)+isin(5π/6), find in its simplest form w^4z^6?

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Question 897851: given z=2+2i; z=cos(5π/6)+isin(5π/6), find in its simplest form w^4z^6?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
given w=2+2i; z=cos(5π/6)+isin(5π/6), find in its simplest form w^4z^6?
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5About 2+2i
r = sqrt(2^2+2^2) = 2^(3/2)
theta = arctan(2/2) = pi/4
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w^4 = (2^(3/2))^4*cis(4(pi/4)) = 64cis(pi)
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About z::
z^6 = cis(5pi)
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Ans: w^4*z^6 = 64cis(6pi)
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Cheers,
Stan H.
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