SOLUTION: Find two consecutive integers whose product is 8 less than the square of the smaller number. (Enter your answers as a comma-separated list.)

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: Find two consecutive integers whose product is 8 less than the square of the smaller number. (Enter your answers as a comma-separated list.)      Log On


   

Question 897678: Find two consecutive integers whose product is 8 less than the square of the smaller number. (Enter your answers as a comma-separated list.)
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
n%28n%2B1%29=-8%2Bn%5E2

n%5E2-n%28n%2B1%29-8=0
n%5E2%2Bn=-8%2Bn%5E2
n=-8

The integers are -8 and -7.

Recheck in equation:
(-8)(-7)=-8+(-8)^2
56=-8+64
56=64-8=56 yes.