SOLUTION: Find three consecutive even integers for which negative four times the sum of the first and the third integers is 192.
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Question 897131
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Find three consecutive even integers for which negative four times the sum of the first and the third integers is 192.
Answer by
CubeyThePenguin(3113)
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consecutive even integers: (x-2), x, (x+2)
-4((x-2) + (x+2)) = 192
2x = -48
x = -24
The integers are -26, -24, and -22.
