SOLUTION: (2^10)(2^2)/2^9
(it's suppose to be two to the tenth times two to the second divided by two to the ninth)
The answer I got was 8.
I used the rule X^7*x^4=X^11 for the top
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-> SOLUTION: (2^10)(2^2)/2^9
(it's suppose to be two to the tenth times two to the second divided by two to the ninth)
The answer I got was 8.
I used the rule X^7*x^4=X^11 for the top
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Question 897102: (2^10)(2^2)/2^9
(it's suppose to be two to the tenth times two to the second divided by two to the ninth)
The answer I got was 8.
I used the rule X^7*x^4=X^11 for the top and the rule that when dividing with the same base you subtract. coming up with 2^3=8 Found 2 solutions by josgarithmetic, MathTherapy:Answer by josgarithmetic(39620) (Show Source):
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(2^10)(2^2)/2^9
(it's suppose to be two to the tenth times two to the second divided by two to the ninth)
The answer I got was 8.
I used the rule X^7*x^4=X^11 for the top and the rule that when dividing with the same base you subtract. coming up with 2^3=8
(