SOLUTION: the sum of the squares of three consecutive integers is 110. Find the numbers

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Question 897000: the sum of the squares of three consecutive integers is 110. Find the numbers
Found 2 solutions by thesvw, Alan3354:
Answer by thesvw(77) About Me  (Show Source):
You can put this solution on YOUR website!
If the smallest number is x.
x%5E2%2B+%28x%2B1%29%5E2+%2B%28x%2B2%29%5E2=+110
x%5E2%2B+x%5E2%2B+2x%2B+1%2B+x%5E2+%2B4x%2B4+=+110
3x%5E2%2B+6x+-105+=0
I used this formula x+=+%28-b+%2B-+sqrt%28b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x=+%28-6+%2B-+36%29%2F6
x=-7 or x=+5
There are 2 solutions.
-7, -6, -5 and 5,6,7

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
the sum of the squares of three consecutive integers is 110. Find the numbers
---------
110/3 =~ 36
sqrt%2836%29+=+6
--> 5, 6 & 7
and -5, -6, -7