SOLUTION: find three consecutive even integers such that the sum of the least integer and the greatest integer is 12 more than the muddle integer
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Question 896985
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find three consecutive even integers such that the sum of the least integer and the greatest integer is 12 more than the muddle integer
Answer by
CubeyThePenguin(3113)
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consecutive even integers: (x-2), x, (x+2)
(x-2) + (x+2) = x + 12
2x = x + 12
x = 12
The integers are 10, 12, and 14.