Question 896963: Andrew is 256 miles away from Casey. They are traveling towards each other. If Casey travels 6 mph faster than Andrew and they meet after 8 hours, how fast was each traveling?
Answer by JulietG(1812)   (Show Source):
You can put this solution on YOUR website! C = A+6
256 miles / 8 hours = 32mph (combined)
A + C = 32
Substitute the value of C from the top equation into the bottom
A + C = 32
A + (A+6) = 32
2A + 6 = 32
Subtract 6 from each side
2A = 26
Divide each side by 2
A = 13
If Andrew travels 13mph, Casey travels 13=6, or 19 mph
In 8 hours, Andrew will have traveled 8*13=104 miles
In 8 hours, Casey will have traveled 19*8=152 miles
104 miles + 152 miles = 256 miles
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