Question 896872: M varies jointly as b and c and inversely as the square of d. If M=12/5 when b=16, c=3, and d=5, find b when M=10, c=4, and d=6.
I set the problem up like this- 10=4b/6^2, but I don't think this is right. If this problem could be explained to me and how to set it up, that would be extremely helpful. Thank you in advance!
Sincerely,
Struggling College Algebra Student
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! M varies jointly as b and c and inversely as the square of d. If M=12/5 when b=16, c=3, and d=5, find b when M=10, c=4, and d=6.
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Your equation requires a constnt of proportionality.
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M = k*b*c/d^2
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Solve for "k" using "M=12/5 when b=16, c=3, and d=5}
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12/5 = k*16*3/5^2
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12/5 = k*48/25
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48k = 60
k = 4/5
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Equatio:
M = (4/5)*b*c/d^2
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Find b when M=10, c=4, and d=6.
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10 = (4/5)b*4/36
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50 = 4b/9
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450 = 4b
b = 112.5
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Cheers,
Stan H.
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