SOLUTION: 4x^2 + 20x + 25

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Question 896789: 4x^2 + 20x + 25
Answer by richwmiller(17219) About Me  (Show Source):
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4x^2 + 20x + 25
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Looking at the expression 4x%5E2%2B20x%2B25, we can see that the first coefficient is 4, the second coefficient is 20, and the last term is 25.



Now multiply the first coefficient 4 by the last term 25 to get %284%29%2825%29=100.



Now the question is: what two whole numbers multiply to 100 (the previous product) and add to the second coefficient 20?



To find these two numbers, we need to list all of the factors of 100 (the previous product).



Factors of 100:

1,2,4,5,10,20,25,50,100

-1,-2,-4,-5,-10,-20,-25,-50,-100



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to 100.

1*100 = 100
2*50 = 100
4*25 = 100
5*20 = 100
10*10 = 100
(-1)*(-100) = 100
(-2)*(-50) = 100
(-4)*(-25) = 100
(-5)*(-20) = 100
(-10)*(-10) = 100


Now let's add up each pair of factors to see if one pair adds to the middle coefficient 20:



First NumberSecond NumberSum
11001+100=101
2502+50=52
4254+25=29
5205+20=25
101010+10=20
-1-100-1+(-100)=-101
-2-50-2+(-50)=-52
-4-25-4+(-25)=-29
-5-20-5+(-20)=-25
-10-10-10+(-10)=-20




From the table, we can see that the two numbers 10 and 10 add to 20 (the middle coefficient).



So the two numbers 10 and 10 both multiply to 100 and add to 20



Now replace the middle term 20x with 10x%2B10x. Remember, 10 and 10 add to 20. So this shows us that 10x%2B10x=20x.



4x%5E2%2Bhighlight%2810x%2B10x%29%2B25 Replace the second term 20x with 10x%2B10x.



%284x%5E2%2B10x%29%2B%2810x%2B25%29 Group the terms into two pairs.



2x%282x%2B5%29%2B%2810x%2B25%29 Factor out the GCF 2x from the first group.



2x%282x%2B5%29%2B5%282x%2B5%29 Factor out 5 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



%282x%2B5%29%282x%2B5%29 Combine like terms. Or factor out the common term 2x%2B5



%282x%2B5%29%5E2 Condense the terms.



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Answer:



So 4%2Ax%5E2%2B20%2Ax%2B25 factors to %282x%2B5%29%5E2.



In other words, 4%2Ax%5E2%2B20%2Ax%2B25=%282x%2B5%29%5E2.



Note: you can check the answer by expanding %282x%2B5%29%5E2 to get 4%2Ax%5E2%2B20%2Ax%2B25 or by graphing the original expression and the answer (the two graphs should be identical).