SOLUTION: The point intersection of the line 2x-y=4 and the parabola y=x^2-3 is:

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Question 896765: The point intersection of the line 2x-y=4 and the parabola y=x^2-3 is:
Answer by Alan3354(69443) About Me  (Show Source):
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intersection of the line 2x-y=4 and the parabola y=x^2-3
2x-y=4 --> y = 2x-4
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y = x^2-3
y = 2x-4
x^2 - 3 = 2x - 4
Solve for x, then for y.
Check for extraneous solutions.