Question 896695: I have a multiple questions, please help me
1 for what condition is the vertex of the graph of the equation y=ax^2+bx+c the highest point of the graph ?
2 describe an algebraic method for determining the x intercepts, if any of a parabola whose equation is y=ax^2+bx+c
3 suppose that the graph of y=ax^2+bx+c is parabola whose vertex is V(-3,7). What is the algebraic interpretation of the 2nd coordinate 7 ?
It is okay if you will not graph the answers .
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! 1) we want a parabola that opens downward, this means that a must be negative
that is in the equation y = ax^2 +bx + c, the a constant is negative (a < 0)
2) Solve the equation y = ax^2 +bx +c for x by setting ax^2 +bx +c = 0 and using the quadratic formula to solve, x = (-b + or - square root of b^2 -4ac) / 2a
3) V is a point on the parabola with x = -3 and y =7, therefore
7 = a(-3)^2 +b(-3) +c
7 = 9a -3b +c
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