SOLUTION: The questions state: Find all values of y such that the distance between (3,y) and (-2,9) is 12. I am stumped and need help PLEASE! thanks!

Algebra ->  Coordinate-system -> SOLUTION: The questions state: Find all values of y such that the distance between (3,y) and (-2,9) is 12. I am stumped and need help PLEASE! thanks!      Log On


   

Question 89667: The questions state:
Find all values of y such that the distance between (3,y) and (-2,9) is 12.
I am stumped and need help PLEASE!
thanks!
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
(3,y) defines a vertical line at x=3 ... all the points at a distance of 12 units from point (-2,9) is a circle

since the line is less than 12 units from the point, the line will intersect the circle in two places

the general formula for a circle of radius r centered at (h,k) is (x-h)^2+(y-k)^2=r^2 ... in this case (3-(-2))^2+(y-9)^2=144

25+(y-9)^2=144 ... (y-9)^2=119 ... y-9=%2B-+%28sqrt%28119%29%29 ... y=9%2B-sqrt%28119%29